Practice Question
Interpret the following. ABG: pH 7.49, pC02 30 mmHg, HC03 23 Meq/L, Pa02 96 mmHg SaO2 98%
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Correct Answer:
respiratory alkalosis
Rationale:
🔷 Respiratory alkalosis is indicated by the elevated pH (7.49) and low PaCO₂ (30 mmHg), as the body compensates by hyperventilating and exhaling excess CO₂.
🔷 The normal bicarbonate level (HCO₃ of 23 mEq/L) suggests no metabolic compensation yet.
🔷 PaO₂ and SaO₂ are within normal limits, indicating the respiratory alkalosis has not caused significant hypoxia.
🔷 Respiratory alkalosis can be caused by anxiety, pain, or hyperventilation.
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This question is from NUR 133~Acid-base & Electrolytes Exam 2 which contains 74 questions.
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Question Details
- Category: RN Nursing Exam(s)
- Subcategory: ATI Exam(s)
- Domain: Fluids and Electrolytes
- Answer Choices: 4